Math, asked by krishnendu41, 7 months ago

solve this
x²-y²-z²+2yz

Answers

Answered by ankita2411

2

Answer:

x²-y²+2yz-z²

x²-y²+2yz-z²=x²-(y²-2yz+z²)

x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²

x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²=(x+y-z)(x-y+z).

Answered by Sumanthreddy651022

0

Answer:

= x²-y²+2yz-z²

= x²-y²+2yz-z²=x²-(y²-2yz+z²)

= x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²

= x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²=(x+y-z)(x-y+z).

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