solve this
x²-y²-z²+2yz
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Answer:
x²-y²+2yz-z²
x²-y²+2yz-z²=x²-(y²-2yz+z²)
x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²
x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²=(x+y-z)(x-y+z).
Answered by
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Answer:
= x²-y²+2yz-z²
= x²-y²+2yz-z²=x²-(y²-2yz+z²)
= x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²
= x²-y²+2yz-z²=x²-(y²-2yz+z²)=x²-(y-z)²=(x+y-z)(x-y+z).
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