Question

solve this;
x⁴- 13x² + 36 = 0​

Answer 1

Answer:

x = ±3

x = ±2

Step-by-step explanation:

x⁴- 13x² + 36 = 0​

u=x²

u² - 13u + 36 = 0

(u - 9)(u - 4) =0

u - 9 = 0

u = 9

x² = 9

x = ±3

u - 4 = 0

u = 4

x² = 4

x = ±2

Answer 2

Given,

the equation given is: $x^{4}- 13x^{2}+36=0$

To Find,

values of x.

Solution,

$x^{4}- 13x^{2}+36=0$                            (1)

let u = $x^{2}$

so equation (1) becomes,

$u^{2}-13u+36=0\\ \\(u-9)(u-4)=0\\\\u-9=0\\\\u=9\\x^{2} =9$

x = ± 3

u-4=0

u=4

$x^{2} =4$

x = ±2

Hence the values of x= ± 3 and x = ±2.