solve this y/2-1/2=y/3+1/4
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hope this will help u .
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SOLUTION 2 : Begin with (x-y)2 = x + y - 1 . Differentiate both sides of the equation, getting
D (x-y)2 = D ( x + y - 1 ) ,
D (x-y)2 = D ( x ) + D ( y ) - D ( 1 ) ,
(Remember to use the chain rule on D (x-y)2 .)
,
2 (x-y) (1- y') = 1 + y' ,
so that (Now solve for y' .)
2 (x-y) - 2 (x-y) y' = 1 + y' ,
- 2 (x-y) y' - y' = 1 - 2 (x-y) ,
(Factor out y' .)
y' [ - 2 (x-y) - 1 ] = 1 - 2 (x-y) ,
D (x-y)2 = D ( x + y - 1 ) ,
D (x-y)2 = D ( x ) + D ( y ) - D ( 1 ) ,
(Remember to use the chain rule on D (x-y)2 .)
,
2 (x-y) (1- y') = 1 + y' ,
so that (Now solve for y' .)
2 (x-y) - 2 (x-y) y' = 1 + y' ,
- 2 (x-y) y' - y' = 1 - 2 (x-y) ,
(Factor out y' .)
y' [ - 2 (x-y) - 1 ] = 1 - 2 (x-y) ,
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