solve this : y^3=(1+p^2)
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Can we will talk on this topic later on another question.
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(p+1)x-(2p+3)y-1=0x = 2y = 3(p+1)x-(2p+3)y-1=0px + x -( 2py +3y) -1 =0px + x -2py - 3y -1= ... More
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