Math, asked by DAVIDSAM, 1 year ago

solve this y²+6y-265+18=0

Answers

Answered by Anonymous
4
hey \: \\ here \: is \:your \: answer \: \\ {y}^{2} + 6y \: - 247 = 0 \\ {y}^{2} + 19y - 13y - 247 = 0 \\ y(y + 19) - 13(y + 19)
Hence the answer isx = -19 or x = 13

hope \: it \: helps
Answered by Panzer786
8
Heya !!!

Y² + 6Y - 265 + 18

Y² + 6Y - 247

★ 247 × 1 = 247

We try to split 247 in two parts such that their sum or subtraction will be 6 and product will be 247.

Clearly,

19 - 13 = 6

And,

19 × 13 = 247

So,

Y² + 6Y - 247

Y² + 19Y - 13Y - 247

Y ( Y + 19 ) - 13 ( Y + 19 )

( Y + 19 ) ( Y - 13 ) = 0

( Y + 19 ) = 0 OR ( Y - 13 ) = 0

Y = -19 OR Y = 13

★ HOPE IT WILL HELP YOU ★
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