Question

Solve this. You have two bags of 100 coins each. You have to make just one operation so that the coins in one bag are exactly the double of coins in the other bag. Conditions: 1. You cannot cut the coins. 2. You have to work with these 200 coins only. 3. No more than one operation allowed. 4. Coins cannot be thrown away. They have to be in one of the bags.

Answer 1

kept bag one in to another bag.

Answer 2

Answer:

Split the coins into 190 and 10.

Step-by-step explanation:

Given:

To find:

Make 2 piles with 10 coins and 90 coins each. Now, flip all the coins in the smaller pile.  

Solution:

Make 2 piles and say pile one has ‘h’ no. of heads and ‘t’ no. of tails while the other pile will have ’10-h’ heads and ’190-t’ tails. Now we can flip coins of one pile, so lets flip coins of any pile(say 2nd pile) then no. of heads and tails interchange and now no. of heads are ’190-t’ and no. of tails are ’10-h’.

Now no. of heads in pile 1 = no. of heads in pile 2

h=90-t

Therefore, h+t=90

And no. of coins in pile 1 is ‘h+t’

So, split the coins into 190 and 10.