Math, asked by pallaviawarke1982, 7 months ago

Solve thisss plzzz........

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Answered by Kanak007vats

Step-by-step explanation:

just open brackets and multiply them with each other

hope u would understand...

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Answered by Mihir1001

$\huge{\underline{\mathfrak{\textcolor{blue}{Answer :}}}}$

( a ) $\Large\boxed{(3 {x}^{3} + 2x - 5) + (2 {x}^{2} + x - 9) \: = \: 3 {x}^{3} + 2 {x}^{2} + 3x - 14}$

( b ) $\Large\boxed{(b + 1.4c) + ( - 0.6b + 2) \: = \: 0.4b + 1.4c + 2}$

$\LARGE{\underline{\mathrm{\textcolor{red}{Step-by-step \: \: explanation :}}}}$

$\LARGE{\underline{\mathtt{\textcolor{violet}{Given :-}}}}$

a) $(3 {x}^{3} + 2x - 5) + (2 {x}^{2} + x - 9)$

b) $(b + 1.4c) + ( - 0.6b + 2)$

$\LARGE{\underline{\mathtt{\textcolor{green}{To \: \: find :-}}}}$

Sum

$\LARGE{\underline{\mathtt{\textcolor{teal}{Concept \: \: used :-}}}}$

Addition of polynomials

$\LARGE{\underline{\mathtt{\textcolor{blue}{Solution :-}}}}$

$\large\boxed{a}$

$(3 {x}^{3} + 2x - 5) + (2 {x}^{2} + x - 9)$

$= 3 {x}^{3} + 2x - 5 + 2 {x}^{2} + x - 9$

$= 3 {x}^{3} + 2 {x}^{2} + (2 + 1)x - (5 + 9)$

$= 3 {x}^{3} + 2 {x}^{2} + 3x - 14$

$\large\boxed{b}$

$(b + 1.4c) + ( - 0.6b + 2)$

$= b + 1.4c - 0.6b + 2$

$= (1 - 0.6)b + 1.4c + 2$

$= 0.4b + 1.4c + 2$

$\LARGE{\underline{\mathtt{\textcolor{magenta}{Conclusion :-}}}}$

$\boxed{(3 {x}^{3} + 2x - 5) + (2 {x}^{2} + x - 9) \: = \: 3 {x}^{3} + 2 {x}^{2} + 3x - 14}$

$\boxed{(b + 1.4c) + ( - 0.6b + 2) \: = \: 0.4b + 1.4c + 2}$

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