Question

solve thissssss
please ​

Answer 1

Answer:

hope this answer will help you dude

Answer 2

Answer:

10 is the answer

Step-by-step explanation:

$\frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } + \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

At first we have to rationalise their denominators in order to add them

${\small{\implies{\mathtt({\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\times \frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})+(\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}\times\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}}}}})$

${\small{\implies{\mathtt{\frac{(\sqrt{3}+\sqrt{2})^{2}}{(\sqrt{3})^{2}-(\sqrt{2})^{2}}+\frac{(\sqrt{3}-\sqrt{2})^{2}}{(\sqrt{3})^{2}-(\sqrt{2})^{2}}}}}}$

Using identity

1. (a+b)² = a² + b² + 2ab
2. (a-b)² = a² + b² - 2ab

We get ,

${\small{\implies{\mathtt{\frac{3+2+2\sqrt{6}}{3-2} + {\frac{3+2-2\sqrt{6}}{3-2}}}}}}$

${\small{\implies{\mathtt{5+2\sqrt{6}+5-2\sqrt{6}}}}}$

${\small{\implies{\mathtt{5+5}}}}$

${\small{\boxed{\implies{\mathtt{\red{10\:is \:the\: required\: answer}}}}}}$