Question

solve through 9x²-3x-2=0 completing the squares method.
step by step please​

Answer 1

Answer:

$9x {}^{2} - 3x - 2 = 0$

$x = \frac{ - b ± \sqrt{b {}^{2} - 4ac } }{2a}$

$x = \frac{3 ± \sqrt{( - 3) {}^{2} - 4(9)( - 2)} }{2 \times 9}$

$x = \frac{3 ± \sqrt{9 + 72} }{18}$

$x = \frac{3 ± \sqrt{81} }{18}$

$x = \frac{3 + 9}{18} \: \: and \: \frac{3 - 9}{18}$

$x = \frac{12}{18} \: and \: \frac{ - 6}{18}$

$x = \frac{2}{3} \: and \: \frac{ - 1}{3}$