Solve through Truth Table:
i. (X+Y'+Z)+X'Y'
please answer fast....
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Answer:
truth table:
X Y Z YZ X+Y X+Z (X+Y)(X+Z) X+YZ
0 0 0 0 0 0 0 0
0 0 1 0 0 1 0 0
0 1 0 0 1 0 0 0
0 1 1 1 1 1 1 1
1 0 0 0 1 1 1 1
1 0 1 0 1 1 1 1
1 1 0 0 1 1 1 1
1 1 1 1 1 1 1 1
(c) X'Y + Y'Z + XZ' = XY' + YZ' + X'Z
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