solve thsi and prove this
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SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT
#TOGETHER WE GO FAR✔✔
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Answer:
LHS = ( 1 + secA )/secA
= ( 1 + 1/cosA ) / ( 1/cosA )
= [ ( CosA + 1 ) / cosA ] / ( 1/ cosA )
= Cos A + 1
= ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA )
= ( 1 - cos² A ) / ( 1 - cosA )
= Sin² A / ( 1 - cosA ) = RHS
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