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A simple pendulum takes 40 seconds
complete 12 oscillations. find its time period and frequency .
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Answered by
2
Answer:
0.10
Explanation:
Frequency equals the number of waves that passes a given point per second or the number of oscillations of a vibrating body per second or number of cycles per second.
In this case, A pendulum has a frequency 40 in 4 seconds. Therefore, the frequency of the pendulum in one second is given as f=
timetaken
Noofcycles
=
4
40
=10Hz.
Time period of the wave is defined as the reciprocal of the frequency of the wave.
That is, T=
f
1
=
10
1
=0.1second.
Hence, the frequency and time period of the pendulum are 10 Hz and 0.1 second respectively.
Answered by
0
Answer:
Time period = no. of oscillations / time taken = 12/40 = 0.3 seconds per oscillation
Frequency= time taken/ no. of oscillations= 40/12= 3Hz (approx.)
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