Question

solve to be an brainlist

Answer 1

here is your answer....

hope it will help you..

plz mark it as brainliest ❤️❤️❤️

Answer 2

Hey there !!


Question 6 :- Verify that :-)

$\bf {[ {(729)}^{ \frac{ - 5}{3} } ]} ^{ \frac{ - 1}{2} } = {(729)}^{ \frac{ - 5}{3} \times \frac{( - 1)}{2} } . \\ \\ = {(729)}^{ \frac{ - 5}{3} \times \frac{( - 1)}{2} } = {(729)}^{ \frac{ - 5}{3} \times \frac{( - 1)}{2} }. \\ \\ = {(729)}^{ \frac{5}{6} } = {(729)}^{ \frac{5}{6} } . \\ \\ \huge verified \checkmark \checkmark$

▶ Question 7:- Solve the given exponential equations :-)


$(i) {( \sqrt{6} )}^{x - 2} = 1. \\ \\ = > ({ \cancel{\sqrt{6}} )}^{x - 2} = ({ \cancel{\sqrt{6} })}^{0} . \\ \\ = > x - 2 = 0. \\ \\ = > x = 2. \: ans \checkmark$


[Law used :- If a is a non zero integer then ${a}^{0} = 1$ . ]


$(ii) {3}^{4x} = \frac{1}{81} . \\ \\ = > {3}^{4x} = \frac{1}{ {3}^{4} } . \\ \\ = > { \cancel3}^{4x} = { \cancel3}^{ - 4} . \\ \\ = > 4x = - 4. \\ \\ = > x = \frac{ - 4}{4} . \\ \\ = > x = - 1. \: ans \checkmark$



$(iii) {( \sqrt{2} )}^{x} = {2}^{8} . \\ \\ = > {( \sqrt{2} )}^{x} = {( \sqrt{2} \times \sqrt{2}) }^{8} . \\ \\ = > {( \sqrt{2} )}^{x} = ({ {( \sqrt{2} )}^{2} )}^{8} . \\ \\ = > {( \cancel{\sqrt{2}}) }^{x} = {( \cancel{\sqrt{2}}) }^{16} . \\ \\ = > x = 16. \: ans \checkmark$



$(iv) {2}^{2x + 1} = {4}^{2x - 1} . \\ \\ = > {2}^{2x + 1} = {(2 \times 2)}^{2x - 1} . \\ \\ = > {2}^{2x + 1} = { ({2}^{2} )}^{2x - 1} . \\ \\ = > { \cancel2}^{2x + 1} = { \cancel2}^{4x - 2} . \\ \\ = > 2x + 1 = 4x - 2. \\ \\ = > 4x - 2x = 1 + 2. \\ \\ = > 2x = 3. \\ \\ = > x = \frac{3}{2} .ans \checkmark$


✔✔ Hence, it is solved ✅✅.

____________________________________


THANKS


#BeBrainly.