Question

solve today is my exam
Divide 585 into 3 parts such that the second part is 10 more than twice the first, and the third is 75 more than first. Find the no.s​

Answer 1

Answer:

166.66,343.32,241.66

Step-by-step explanation:

Let the first part be X

Then the Second part be 2 X+10

Third=X+75

So, X+2 X+10+X+75=585

3 X+85=585

3 X=585-85

X = 500/3

X=166.66

2nd=2*166.66+10

2 nd= 343.32

third=166.66+75

Third=241.66

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Answer 2

Answer:

The numbers are 125, 260 and 200.

Step-by-step explanation:

Let the first number be 'x',

Second number = 2x + 10

Third number = x + 75

Equation formed:

x + 2x + 10 + x + 75 = 585

4x + 85 = 585

4x = 585 - 85

4x = 500

x = $\frac{500}{4}$

x = 125

First number = 125

Second number = (2 × 125) + 10 = 260

Third number = 125 + 75 = 200

The sum is also 585 (125 + 260 + 200 = 585), hence, these are the values of the numbers.