Question

solve triangle
AEP~ ADB
PDC~BEC
plz give answer
don't give use less answer
if u do I will report u ​

Answer 1

angle AEP = angle ADB [90 degree]

angle PAE = angle DAB [ common]

therefore AEP ~ ADB [ A.A postulate]

in ∆ PDC AND ∆BEC

angle BEC =angle PDC [90 degree]

angle BEC = angle PCD [common]

therefore PDC~BEC [A.A postulate]