Solve : [Trigonometry]
Sec²x + cosec²x
4
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⏩sec² + cosec² = (1+tan²x)+1(cot²x)
⏩2 + tan²x + cot²x
⏩2 + tan²x +cot²x -2tanx•cotx +2tanxcotx
putting tanx•cotx = 1
⏩2+(tanx - cotx)² +2
⏩4+(tanx -cotx)² >= 4
⏩by using identity
(tanx -cotx)² >= 0
Reason is the tanx and cot x are complementary phased chande of Π
Thank.
☬ ★Your Answer★ ☬
╘═════════════════════╛
⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣
⏩sec² + cosec² = (1+tan²x)+1(cot²x)
⏩2 + tan²x + cot²x
⏩2 + tan²x +cot²x -2tanx•cotx +2tanxcotx
putting tanx•cotx = 1
⏩2+(tanx - cotx)² +2
⏩4+(tanx -cotx)² >= 4
⏩by using identity
(tanx -cotx)² >= 0
Reason is the tanx and cot x are complementary phased chande of Π
Thank.
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