solve triple product [a+b c+d d+e]
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If
b
a
=
3
1
,
c
b
=2,
d
c
=
2
1
,
e
d
=3 and
f
e
=
4
1
, then what is the value of
def
abc
?
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Solution
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Correct option is
A
8
3
Given
b
a
=
3
1
⇒a=
3
b
c
b
=2⇒c=
2
b
d
c
=
2
1
⇒d=2c⇒d=2×
2
b
=b
e
d
=3⇒e=
3
d
⇒e=
3
b
f
e
=
4
1
⇒f=4e⇒f=
3
4b
∴
def
abc
=
b×
3
b
×
3
4b
3
b
×b×
2
b
=
8
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