Question

Solve tw0 linear if coefficients of x and y are interchanged equations

Answer 1

Suppose we are given two equations,

ax + by = c → (1)

and,

bx + ay = d → (2)

We have to solve both the equations. For this, what we have to do is to multiply both equations by a suitable real number constant.

We multiply (1) by b and (2) by a, and hence we get,

abx + b²y = bc → (3)

abx + a²y = ad → (4)

Subtracting (3) from (4) (or the converse), we get,

y = (ad - bc) / (a² - b²)

Now, on giving value of y to any of the equations, we get value of x.

Or, similar to first one, we can multiply (1) by a and (2) by b. Then we get,

a²x + aby = ac → (5)

b²x + aby = bd → (6)

Subtracting (6) from (5) (the converse can be, here also), we get,

x = (ac - bd) / (a² - b²)

Similarly, on taking value of x in any of the equations we get value of y.

Well, the solution is,

(x, y) = (((ac - bd) / (a² - b²)), ((ad - bc) / (a² - b²)))

#answerwithquality

#BAL

Answer 2

Answer:

easy it is

Step-by-step explanation:

u first add them up, then subtract them

then use ur suitable method and simplify the values of x and y :)