Question

solve. Two types of boxes A,B are to be placed in a truck having capacity of 10 tones. When 150 boxes of type A and 100 boxes of type B are loaded in the truck, it weighs 10 tons. but when 260 boxes of type A are loaded in the truck, it can still accommodate 40 boxes of type B. so that it is Fully loaded. Find the weight of each type of box.​

Answer 1

$answer$

Let the weight of box A be x

and weight of box B be y

and 1 ton=1000 kg

So, 150x+100y=10000

260x+40y=10000

Solving the above Equations Simultaneously , we get

x=30

y=55

Hence, Their Sum =30+55=85

Answer 2

Step-by-step explanation:

◓ Answer:-

Given:-

• Number of A type boxes are 150, while the truck capacity of loading weight is 10 ton
• Number Of B type of boxes are 100, while the truck capacity of loading weight is also 10 tones, but when 260 boxes of type A are loaded in the truck, it can still accommodate 40 boxes of type.

To find:-

• The weight of each type of box.

Solution:-

Let the weights of box of type A be x kg and that of box of type B be y kg.

1 ton = 1000 kg

∴ 10 tons = 10000 kg

According to the first condition,

150x + 100y = 10000

∴ 3x + 2y = 200 …(i) [Dividing both sides by 50]

According to the second condition,

260x + 40y = 10000

∴ 13x + 2y = 500 …(ii) [Dividing both sides by 20]

Subtracting equation (i) from (ii), we get,

13x + 2y = 500

3x + 2y = 200

=》 10x = 300

$∴ \: x = \frac{300}{30} \: = \: 30$

Substituting x = 30 in equation (i), we get ,

3(30) + 2y = 200

⇥ 90 + 2y = 200

⇥ 2y + 200 - 90

⇥ 2y = 110

⇥ y= 11021102

⇥ y = 55

☘ Hence, The weight of box of type A is 30 Kg and that of box of type B is 55 Kg.