Question

solve:under root x+7+inder root x-2 /under root x+7- under root x-2 =5/1​

Answer 1

√x+7 + √x-2 = 5

√x+7- √x-2 1

√x+7 + √x-2= 5(√x+7 - √x-2)

√x+7+√x-2= 5√x+7-5√x-2

6√x-2= 4√x+7

on squaring both sides

36(x-2)= 16(x+7)

9(x-2)= 4(x+7)

9x-18= 4x+28

9x-4x= 28-18

5x= 10

x= 10/5= 2

no number can satisfy that equation

an x can't have two value,

but if we were to consider √x+2 instead of √x-2 on both numerator and denominator then only the equation can be solved.