Math, asked by ishapinjara, 10 months ago

Solve up to 2 decimal places: 3x² – x – 7 = 0.​

Answers

Answered by pinjaraarifisha
1

Answer:

\huge{\blue{\boxed{\green{\boxed{\red{\boxed{\bf{\mathbb{\purple{HELLO}}}}}}}}}}

\huge\bold\star\underline\mathbb\orange{Answer\: :)}

<b><i><body bgcolor=lightgreen><font color=red></b></i>

__________

x = 1.70 or -1.36

Step-by-step explanation:

According to the question the given quadratic equation is: "3x² – x – 7 = 0.

Now, we have to use Sridhar Acharya formula:

x = [−b±√(b²−4ac)]/2a

Here a = +3, b = -1 and c = -7.

So, x = [−(-1)±√((-1)²−4*(3)*(-7))]/2*a

or, x = [+1±√(1+84)]/2*3

or, x = [+1±√85]/6

or, x = [+1+√85]/6    or    [+1-√85]/6

or, x = [+1+9.21]/6    or    [+1-9.21]/6

or, x = 10.21/6   or   -8.21/6

or, x = 1.70 or -1.36 [Ans]

Therefore, correct upto 2 decimal places the value of x will be either 1.70 or -1.36.

Thanks Dude!

have A Nice Day (^_^)

__________

<svg width="250" height="250" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="pink" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>

<!DOCTYPE html> <html> <svg width="100%" height="300px">\ \textless \ br /\ \textgreater \ <g id="R1" transform="translate(250 250)"> \ \textless \ br /\ \textgreater \ <ellipse rx="100" ry="0" opacity=".3">\ \textless \ br /\ \textgreater \ <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ </ellipse>\ \textless \ br /\ \textgreater \ </g><use xlink:href="#R1" transform="rotate(72 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(144 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(216 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(288 390 150)" />\ \textless \ br /\ \textgreater \ </svg></body></html>

Answered by rvkinage
0

Step-by-step explanation:

According to the question the given quadratic equation is: "3x² – x – 7 = 0. Here a = +3, b = -1 and c = -7. Therefore, correct upto 2 decimal places the value of x will be either 1.70 or -1.36.

Similar questions