Math, asked by ishapinjara, 8 months ago

Solve up to 2 decimal places: 3x² – x – 7 = 0. ​

Answers

Answered by pinjaraarifisha
2

Answer:

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__________

x = 1.70 or -1.36

Step-by-step explanation:

According to the question the given quadratic equation is: "3x² – x – 7 = 0.

Now, we have to use Sridhar Acharya formula:

x = [−b±√(b²−4ac)]/2a

Here a = +3, b = -1 and c = -7.

So, x = [−(-1)±√((-1)²−4*(3)*(-7))]/2*a

or, x = [+1±√(1+84)]/2*3

or, x = [+1±√85]/6

or, x = [+1+√85]/6    or    [+1-√85]/6

or, x = [+1+9.21]/6    or    [+1-9.21]/6

or, x = 10.21/6   or   -8.21/6

or, x = 1.70 or -1.36 [Ans]

Therefore, correct upto 2 decimal places the value of x will be either 1.70 or -1.36.

Thanks Dude!

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__________

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Answered by Anonymous
6

Answer:

x = 1.70 or -1.36</p><p></p><p>Step-by-step explanation:</p><p></p><p>According to the question the given quadratic equation is: "3x² – x – 7 = 0.</p><p></p><p>Now, we have to use Sridhar Acharya formula:</p><p></p><p>x = [−b±√(b²−4ac)]/2a</p><p></p><p>Here a = +3, b = -1 and c = -7.</p><p></p><p>So, x = [−(-1)±√((-1)²−4*(3)*(-7))]/2*a</p><p></p><p>or, x = [+1±√(1+84)]/2*3</p><p></p><p>or, x = [+1±√85]/6</p><p></p><p>or, x = [+1+√85]/6    or    [+1-√85]/6</p><p></p><p>or, x = [+1+9.21]/6    or    [+1-9.21]/6</p><p></p><p>or, x = 10.21/6   or   -8.21/6</p><p></p><p>or, x = 1.70 or -1.36 [Ans]</p><p></p><p>Therefore, correct upto 2 decimal places the value of x will be either 1.70 or -1.36.</p><p></p><p>Thanks Dude!</p><p></p><p>

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