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using 8r²= r+2 by
quadratic equation !
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Answer:
8r² = r + 2
Let us convert this into the form of ax² + bx + C = 0
=> 8r² - r - 2 = 0
Using the Quadratic Formula, we get:
x = ( -b ±√(b² - 4ac))/2a
So, r =
(-(-1) ±√((-1)²-4(8)(-2))/2(8)
= (1 ±√(1 + 24))/16
= 1 ±√(25)/16
=( 1 ±5)/16
So, the two zeroes are:
i) (1 + 5)/16 = 6/16
= 3/8
ii) (1 - 5)/16 = -4/16
= -1/4
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Thankyou
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