solve using algebraic identity (5x^2+3/4y^2)(5x^2-3/4y^2)
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Use the identity
(a+b)(a-b)=a²-b²
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This is example
Given equations are,
5
y+7
=
4
2y−x
+3x−5
⇒4(y+7)=5(2y−x+12x−20)
⇒4y+28=10y+55x−100
⇒55x+6y=128 ....(1)
and
2
7−5x
+
6
3−4y
=5y−18
⇒3(7−5x)+(3−4y)=6(5y−18)
⇒21−15x+3−4y=30y−108
⇒15x+34y=132 ....(2)
Multiply (1) by 3 and (2) by 11, we get
165x+18y=384
165x+374y=1452
Subtracting above equations we get
356y=1068⟹y=3
Put value of y in (1)
we get x=2
∴x=2,y=3
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