solve using any thing 4x+3y=65 and x+2y=35
Answers
Answered by
2
Suppose we use elimination method to get answer: 4x+3y=65 is equation 1 and X +2Y =35 is equation 2.
(4x+3y=65) x 1
(x+2y=35) x 4
So it forms 4x+3y=65 and 4x+8y=140
Now we should Subtract eq 2 from eq1
4x+3y=65
4x+8y=140
——————
-5y= -75
So,y=15
Putting y=15 in eq2
So,x+2y=35
x+2(15)=35
x+30=35
x=35-30
Therefore x=5
You can also put in eq 2 and the same answer u will get it
Hope u like this answer
Mark me brainliest.
(4x+3y=65) x 1
(x+2y=35) x 4
So it forms 4x+3y=65 and 4x+8y=140
Now we should Subtract eq 2 from eq1
4x+3y=65
4x+8y=140
——————
-5y= -75
So,y=15
Putting y=15 in eq2
So,x+2y=35
x+2(15)=35
x+30=35
x=35-30
Therefore x=5
You can also put in eq 2 and the same answer u will get it
Hope u like this answer
Mark me brainliest.
Similar questions