Question

Solve using BODMAS rule:

63 − [(−3){−2 − 5}] ÷ [3{5 + 2}]​

Answer 1

Complete step-by-step answer:

Mathematical operations such as addition, subtraction, multiplication, and division are included in arithmetic operations. In order to arrive at the correct answer, arithmetic operations must be solved in a specific order. For solving according to specific priority, we use the BODMAS rule.

BODMAS stands for Brackets, Order, Division, Multiplication, Addition and Subtraction. This means that:

First, the expressions within the brackets (), {}, are to be solved irrespective of the operators inside the brackets.

Next, the square roots and numbers with powers are to be solved. The O in BODMAS stands for Of or Order.

Then, we must solve the division operation, followed by multiplication, addition, and lastly, subtraction.

Now we can proceed to solve the question as follows:

First, the round brackets () will be solved

=63+3[{−2−8−3¯¯¯¯¯¯¯¯¯¯¯}+3{5+2}]

Next, we will solve the curly brackets {}. Inside the {}, we will first solve addition and then subtraction.

=63+3[{−2−8−3¯¯¯¯¯¯¯¯¯¯¯}+3{7}]

=63+3[{−2−5}+3{7}]

=63+3[{−7}+3{7}]

Now we will multiply the number adjacent to {}

=63+3[−7+21]

Solving the final bracket , we get,

=63+3[14]

Multiplication will take precedence over addition. Hence, we will get,

=63+42

=105

Hence 63−(−3)[{−2−8−3¯¯¯¯¯¯¯¯¯¯¯}+3{5+(−2)(−1)}]=105

.

So, the correct answer is “105”.