solve using by quadratic
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31
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Question :-
x^2 -(√3+1)x+√3 = 0
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Solution :-
x^2 -(√3+1)x+√3 = 0
x^2-√3x - x +√3 = 0
x(x-√3) - 1(x-√3) = 0
(x-√3) (x-1) = 0
x-√3 = 0 or x-1 = 0
x = √3 or x = 1
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Answered by
8
Answer:
x²- (√3+ 1)x + √3 = 0
x²- √3x - x + √3 = 0
x(x - √3 ) - 1(x - √3) = 0
x - √3 = 0 x - 1 = 0
x = √3 x = 1
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