Math, asked by Anonymous, 8 months ago

solve using by quadratic ​

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Answered by Anonymous
31

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Question :-

x^2 -(√3+1)x+√3 = 0

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Solution :-

x^2 -(√3+1)x+√3 = 0

x^2-√3x - x +√3 = 0

x(x-√3) - 1(x-√3) = 0

(x-√3) (x-1) = 0

x-√3 = 0 or x-1 = 0

x = √3 or x = 1

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Answered by Anonymous
8

Answer:

\green{ANSWER}

x²- (√3+ 1)x + √3 = 0

x²- √3x - x + √3 = 0

x(x - √3 ) - 1(x - √3) = 0

x - √3 = 0 x - 1 = 0

x = √3 x = 1

\blue{THANK YOU}

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