Question

solve using by quadratic ​

Answer 1

Answer:

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Answer 2

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Question:-

${x}^{2} - ( \sqrt{3} + 1) x+ \sqrt{3} = 0$

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Solution :-

${x}^{2} - ( \sqrt{3} + 1)x + \sqrt{3} = 0$

$> {x}^{2} - \sqrt{3} x - x - \sqrt{3} = 0 \\ \\ > x(x - \sqrt{3}) - 1(x - \sqrt{3} ) = 0 \\ \\ > (x - 1)(x - \sqrt{3} ) = 0$

Now we have to solve last step of this question

(1)

$(x - 1) = 0 \\ \\ x = 1$

(2)

$x - \sqrt{3} = 0 \\ \\ x = \sqrt{3}$

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We have solve quadratic equations like this. In this we have first factorize the equation and solve it .

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Hope this helps you

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