solve using cross multiplication 2x+3y-17=0 and 3x-zy-6=0
Answers
Answer:
x=4 and y=3
Step-by-step explanation:
Given : Equation 2x+3y=172x+3y=17 and 3x-2y=63x−2y=6
To find : Solve the system of equation by method of cross multiplication?
Solution :
Let Coefficient of x - A
Coefficient of y - B
Constant term - C
Method of cross multiplication is
x y -1
B C C A A B
3 -17 -17 2 2 3
-2 -6 -6 3 3 -2
Cross multiply,
x y -1
(-18-(34)) (-51-(-12)) (-4-9)
(-52) (39) (-13)
Comparing x , i.e. \frac{x}{-52}=\frac{1}{13}−52x=131
x=\frac{-52}{13}x=13−52
x=4x=4
Comparing y , i.e. \frac{y}{39}=\frac{1}{13}39y=131
y=\frac{39}{13}y=1339
y=3y=3
Therefore, The value of x is 4 and the value of y is 3.
Step-by-step explanation:
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ourosolve using cross multiplication 2x+3y-17=0 and 3x-zy-6=0