Solve using cross multiplication method
1.) 2x – y = 3
4x + y = 3
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2x-y-3=0
2x-y=3.....(I)
similarly,4x+y=3....(II)
adding (1) & (2)
6x=6
x=6/6=1
substitute x=1 in equation (1)
we get,2x-y=3
2(1)-y=3
y=-1
hence,x=1 & y=-1
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