#: Solve using cross multiplication method:
2x=5y+4 : 3x-2y+16=0
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Answer:
2x-5y-4=0___(1)×3
3x-2y+16=0______(2)×2
from equation (1)&(2)
6x-15y-12=0____(1)
6x-4y+32=0____(2)
___________
-11y-44=0
-11y=44
y=-4
from equation, (1)
2x+20-4=0
2x+16=0
2x=-16
x=-8
I hope you understand
plz mark as brainleast
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