solve using cross-multiplication method :
4x+3y=17/3x-4y+6=0
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Answer:
Solve equation [2] for the variable x
[2] 3x = 4y - 6
[2] x = 4y/3 - 2
// Plug this in for variable x in equation [1]
[1] 4•(4y/3-2) + 3y = 17
[1] 25y/3 = 25
[1] 25y = 75
// Solve equation [1] for the variable y
[1] 25y = 75
[1] y = 3
// By now we know this much :
x = 4y/3-2
y = 3
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