Question

Solve using cross multiplication method x + y equal to 7 and 2 x minus 3 y equal to 11

Answer 1

Answer:

x+y = 7 => x+y-7=0

2x-3y = 11 => 2x-3y-11=0

then by cross multiplication method

$\frac{x}{1\times(-11)-(-3)\times(-7)} \\ =\frac{y}{- 7\times2-(-11)\times1}\\ = \frac{1}{1\times(-3)-2\times1}$

$\frac{x}{ - 11 - 21} = \frac{y}{ - 14 + 11} = \frac{1}{ - 3 - 2}$

$\frac{x}{ - 32} = \frac{y}{ - 3} = \frac{1}{ - 5}$

$let \: \frac{x}{ - 32} = \frac{1}{ - 5}$

$x = \frac{32}{5}$

$let \: \frac{y}{ - 3} = \frac{1}{ - 5}$

$y= \frac{3}{5}$