Solve using Elimination by Substidection 5x-3y=8; 3x + y = 2
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by elimination method
5x-3y=8
3x+ y=2
take the constants to this side
5x-3y-8=0 •••• eq1
3x+ y-2=0 •••• eq2
take lcm of 5,3=15
now multiply eq 1 with 3 and eq 2 with 5
15x-9y-24=0
15x+5y-10=0
now subtract eq1 from eq2
14y+14=0 y=-1
substitute y=-1 in equation to get value of x
15x+9-24=0 15x=15 x=1
therefore y=-1, x=1
hope it's help ful to all
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