Question

solve using elimination method
2x - 7y +41 = 0
- 3x + 5y = 34​

Answer 1

Answer:

$x = - 3 \\ y = 5$

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Answer 2

Given ,

Equations are.

2x - 7y +41 = 0 ---(1)

- 3x + 5y = 34 ----(2)

Take eq (1)

2x - 7y + 41 = 0

2x - 7y = (-41)

Multiplying both sides with (-)

-2x + 7y = 41 ------ (3)

Compare , eq (2) and (3),

In order to eliminate x we need to multiply eq(3) with 3 and eq (2) with 2

=} eq(3) × 3

= -6x + 21y = (41×3)

= (-6x + 21y = 123)

=} eq(2) ×2

= -6x + 10y = (34×2)

= -6x + 10y = 68

multiply both sides with (-)

= 6x - 10y = -68.

Now compare both equations ;

-6x + 21y = 123

6x - 10y = -68

---------------------

11y = 55

=} y = 5

Now place this y in eq(1)

=} 2x - 7(5) + 41 = 0

2x - 35 + 41 = 0

2x + 6 = 0

=} x = -3

Therefore the values of x and y are (-3) , (5) respectively.