Question

Solve using elimination method
6x+7y-11=0; 5x+2y=13.​

Answer 1

Answer:

$x = 3 \: \: \: \: y = - 1$

Step-by-step explanation:

$6x + 7x - 11 = 0 \\ 6x + 7y = 11 \: \: \: \: \: \: < 1 > \\ \\ 5x + 2y = 13 \: \: \: \: < 2 >$

multiply eq (1) by 2 and eq by(7)

$12x + 14y = 22 \: \: \: < 3 > \\ 35x + 14y = 91 \: \: \: < 4 >$

eq(4)-eq(3)

$35x + 14y = 91 \\ 12x + 14y = 22 \\ - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: 23x = 69 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 3$

put x=3 in eq (3)

$5 \times 3 + 2y = 13 \\ 15 + 2y = 13 \\ 2y = 13 - 15 \\ 2y = - 2 \\ y = - 1$