Math, asked by sahana57, 11 months ago

solve using exponents​

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Answered by daizy5
0

Answer:

no.2

3x=9x+5

3x-9x=5

-6x=5

x=5/-6

no.3

3x=27²

3x=(3³)²

3x=3⁶

x=3⁶/3¹

x=3⁶-¹

x=3⁵

Answered by AA5993
0

Step-by-step explanation:

a) 4^t= 4^6 - t

as the base are same we can equate the powers, therefore

t=6- t

t+t=6

2t=6

t=3

b) 3x = 9^x+5

3x =3^2*x+5

3x=3^2x+10

As the base are same therefore we can equate the powers therefore

x=2x+10

x-2x=10

-x=10

c)9^x=27^2

3^2*x=3^3*2

3^2x=3^6

as the base are same therefore we can equate the powers

2x=6

x=3

d) 9^2x-5 = 27

3^2*2x-5=3^3

3^4x-10=3^3

as the base are same therefore we can equate the powers

4x-10=3

4x=3+10

x=13/4

x=3.2

Here in all the questions the main moto is to convert all the bases same so that we can equate them

hope it's helpful

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