Question

Solve using factorisation. -27y = 2y2 + 13 ​

Answer 1

Answer:

The factors of $-27y=2y^{2}+13$  are   $(y-13)$  and  $(y-\frac{1}{2} )$

Step-by-step explanation:

The given polynomial can be rewritten as $2y^{2}+27y+13=0$

then by using quadratic formula

$y=\frac{-b}{2a}$±$\frac{\sqrt{b^{2}-4ac } }{2a}$,

here $a=2,b=27,c=13$

substituting directly to the formula,

$y=\frac{27}{4}$±$\frac{\sqrt{729-104} }{4}$

  $=\frac{27}{4}$±$\frac{\sqrt{625} }{4}$

  $=\frac{27+25}{4}$   or    $\frac{27-25}{4}$

  $=\frac{52}{4}$    or   $\frac{2}{4}$

  $=13$    or   $\frac{1}{2}$.

hence the answer

thank you