Math, asked by snssj, 1 year ago

solve using formula method ​

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Answered by kaustubdevadiga
3
{b \: + \sqrt{ {b}^{2} - 4ac} } \div 2a \\ \\ 5+ \sqrt{ {5}^{2} - 4 \times 2 \times } 3 \: \div 2 \times 2 \\ \\ 5 + \sqrt{25 - 24} \div 4 \\ \\ 5 + \sqrt{1 \:} \div 4 \\ \\ x = 5 + 1 \div 4 \: \: or \: x = 5 - 1 \div 4 \\ \\ x = 6 \div 4or \: x = 4 \div 4 \\ \\ x = 3 \div 2 \: or \: 1

x=3/2 or x=1

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