solve using formula method. x square - 4 x minus 8 is equal to zero...plzzz solve
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FOR A QUADRATIC EQUATION AX^2+BX+C
ROOTS ARE GIVEN BY
X = -B + √(B^2-4AC) / 2A
HERE
A = 1
B = -4
C= -8
X = -(-4) +√[(-4) ^2 -4(1) (-8) ] / 2×(1)
X = 4 + √( 16 + 32) / 2
X = 4 + 4√3 /2
X = 2 + 2√3
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