Solve using formula x² + 6x + 5 = 0
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Answered by
121
Hi ,
Compare x² + 6x + 5 = 0 with ax² + bx + c = 0 ,
a = 1 , b = 6 , c = 5
discreaminant ( D ) = b² - 4ac
D = 6² - 4 × 1 × 5
D = 36 - 20
D = 16
√D = ± 4 ---( 1 )
By Quadratic formula ;
x = [ ( -b ± √D )/2a ]
x = [ ( -6 ± 4 )/( 2 × 1 ) ]
x = ( -6 + 4 )/2 ] or x = ( -6 - 4 )/2
x = -2/2 or x = -10/2
x = -1 or x = -5
I hope this helps you.
: )
Compare x² + 6x + 5 = 0 with ax² + bx + c = 0 ,
a = 1 , b = 6 , c = 5
discreaminant ( D ) = b² - 4ac
D = 6² - 4 × 1 × 5
D = 36 - 20
D = 16
√D = ± 4 ---( 1 )
By Quadratic formula ;
x = [ ( -b ± √D )/2a ]
x = [ ( -6 ± 4 )/( 2 × 1 ) ]
x = ( -6 + 4 )/2 ] or x = ( -6 - 4 )/2
x = -2/2 or x = -10/2
x = -1 or x = -5
I hope this helps you.
: )
Answered by
1
Answer:
x=-5 OR x=-1
Step-by-step explanation:
x² + 6x + 5 =0
x² + 5x + x + 5 =0
x(x+5) +1(x+5) =0
(x+5) (x+1) = 0
x+5=0 OR x+1= 0
x=-5 OR x=-1
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