Question

solve using formula

y²+1/3y=2


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Answer 1

Answer:

roots are (-1 + √73)/6 and (-1 - √73)/6

Step-by-step explanation:

y² + 1/3 y = 2

first of all resolve it in general form ay² + by + c = 0 .

e.g., y² + 1/3 y = 2

=> 3y² + y = 2 × 3

=> 3y² + y - 6 = 0

if ay² + by + c = 0

then, y = {-b ± √(b² - 4ac)}/2a use it here,

3y² + y - 6 = 0

so, y = {-1 ± √(1² - 4.3(-6))}/2(3)

= {-1 ± √(1 + 72)}/6

= (-1 ± √73)/6

hence, roots are (-1 + √73)/6 and (-1 - √73)/6

Answer 2

Answer:

(-1+√73)/6

(-1-√73)/6