Question

Solve using identities
1.(x +12)whole power 2
2. (x+13)whole power 2
3.(x-15)whole power 2
4.(x –19)whole power 2
5.(x +10)whole power 2

Answer 1

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(x+12)²

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Formula used:-

(a+b)²=a²+b²+2ab

(x+12)²=x²+12²+2(x)(12)

=>x²+144+24x

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\orange{Question\;2:-}}}}$

(x+13)²

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\green{Solution:-}}}}$

Formula used:-

(a+b)²=a²+b²+2ab

(x+13)²=x²+13²+2(x)(13)

=>x²+169+26x

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\orange{Question\;3:-}}}}$

(x-15)²

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\green{Solution:-}}}}$

Formula used:-

(a-b)²=a²+b²-2ab

(x-15)²=x²+15²-2(x)(15)

=>x²+225-30x

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(x-19)²

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\green{Solution:-}}}}$

Formula used:-

(a-b)²=a²+b²-2ab

(x-19)²=x²+19²-2(x)(19)

=>x²+361-38x

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\orange{Question\;5:-}}}}$

(x+10)²

$\tt\it\bf\it\large\bm{\mathcal{\fcolorbox{blue}{white}{\green{Solution:-}}}}$

Formula used:-

(a+b)²=a²+b²+2ab

(x+10)²=x²+10²+2(x)(10)

=>x²+100+20x