Question

Solve using identities
1.(x +12)whole power 2
2. (x+13)whole power 2
3.(x-15)whole power 2
4.(x –19)whole power 2
5.(x +10)whole power 2

Answer 1

Answer:

1)

${(x + 12)}^{2} \\ = {x}^{2} + {(12)}^{2} + 2(x)(12) \\ = {x}^{2} + 144 + 24x$

2)

${(x + 13)}^{2} \\ = {x}^{2} + {13}^{2} + 2(x)(13) \\ = {x}^{2} + 169 + 26x$

3)

${(x - 15)}^{2} \\ = {x}^{2} + {(15)}^{2} - 2(x)(15) \\ = {x}^{2} + 225 - 30x$

4)

${(x - 19)}^{2} \\ = {x}^{2} + {(19)}^{2} - 2(x)(19) \\ = {x}^{2} + 361 - 38x$

5)

${(x + 10)}^{2} \\ = {x}^{2} + {(10)}^{2} + 2(x)(10) \\ = {x}^{2} + 100 + 20x$

Hope it helps you.

plz Mark it as brainliest.

Answer 2

$\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}$

${\large{\purple{\mathbb{ANSWER}}}}$

${\small{\green{\bold{\underline{Identities\:Used:-}}}}}$

▪︎ (a+b)² = a²+2ab+b². ---(1)

▪︎ (a-b)² = a²-2ab+b². ---(2)

${\large{\bold{\red{Now,}}}}$

1. (x+12)²

= x²+2(x)(12)+(12)².

{From id (1)}

= x² + 24x + 144.

2. (x+13)²

{From id(1)}

= x²+2(x)(13)+(13)².

= x² + 26x + 169.

3. (x-15)²

{From Id (2)}

= x²-2(x)(15)+(15)²

= x² - 30x + 225.

4. (x-19)².

{From id(2)}

= x²-2(x)(19)+(19)².

= x² - 38x +361.

5. (x+10)².

{From id(1)}

= x²+2(x)(10)+(10)².

= x² + 20x + 100.

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST.

And remember to always keep a smile on face:D

$<marquee>✌✌THANKS✌✌</marquee>$