solve using identities 5 (2a – 7) (2a – 7 )
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Answer:
(2a−7)(2a−7)=(2a−7)
2
using identity (a−b)
2
=a
2
−2ab+b
2
(2a−7)
2
=(2a)
2
−2×2a×7+7
2
(2a−7)
2
=4a
2
−28a+49
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