solve using identities i) ii)
iii) iv) PLZ PLZ HELP ME ITS URGENT
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1) (2x-1/2x)²=2x²+1/2x²-2(2x)(1/2x)
=2x²+1/2x²-2
2) (3a-1/4b)³=9a³-1/64b³+3(3a)(-1/4b)²+3(3a)²(-1/4b)
=9a³-1/64b³+9a/16b²-27a²/4b
3) (95)= (100-5)(100-5)=(100-5)²
=10000+25-2(100)(5)
=10025-1000
=9025
4) (1/6x+1)³=1/216x³+1+3(1/6x)(1)²+3(1/6x)²(1)
=1/216x³+1+1/2x+1/12x²
=2x²+1/2x²-2
2) (3a-1/4b)³=9a³-1/64b³+3(3a)(-1/4b)²+3(3a)²(-1/4b)
=9a³-1/64b³+9a/16b²-27a²/4b
3) (95)= (100-5)(100-5)=(100-5)²
=10000+25-2(100)(5)
=10025-1000
=9025
4) (1/6x+1)³=1/216x³+1+3(1/6x)(1)²+3(1/6x)²(1)
=1/216x³+1+1/2x+1/12x²
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