Question

solve using identity 103 * 98

Answer 1

(100+3)(100-2)=10000+(3+(-2))100+(3)(-2)
=10000+(1)100-6
=10000+100-6=10094

Answer 2

Hi ,


***********************

We know the algebraic identity

( x + a ) ( x + b ) = x² + ( a + b ) x + ab

****************************

103 × 98

= ( 100 + 3 ) [ 100 + ( - 2 ) ]

= ( 100 )² + [ 3 + ( - 2 ) ] × 100 + 3 ( - 2 )

= 10000 + 100 - 6

= 10000 + 94

= 10094

I hope this helps you.

:)