Question

Solve using identity 103 * 98.​

Answer 1

$Answer:-$

Hi ,

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We know the algebraic identity

( x + a ) ( x + b ) = x² + ( a + b ) x + ab

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103 × 98

= ( 100 + 3 ) [ 100 + ( - 2 ) ]

= ( 100 )² + [ 3 + ( - 2 ) ] × 100 + 3 ( - 2 )

= 10000 + 100 - 6

= 10000 + 94

= 10094

I hope this helps you.

:)