Math, asked by JrEinstein, 11 months ago

solve using identity : 2a^5– 54 a^2​

Answers

Answered by jinadevkv
3

2a⁵ - 54a² = 0

2a²(a³ - 27) = 0

2a² = 0 or a³ - 27 = 0

a² = 0 or a³ = 27

a = 0 or a = 3

Answered by isha6817
2

2a^5-54a^2 = 2(a^5-27a^2)=0=>a^5-27a^2=0=> a^2(a^3-3^3)=0=> a^3-3^3=(a-3)(a^2+3a+9) ans.

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