solve using identity : 2a^5– 54 a^2
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Answered by
3
2a⁵ - 54a² = 0
2a²(a³ - 27) = 0
2a² = 0 or a³ - 27 = 0
a² = 0 or a³ = 27
a = 0 or a = 3
Answered by
2
2a^5-54a^2 = 2(a^5-27a^2)=0=>a^5-27a^2=0=> a^2(a^3-3^3)=0=> a^3-3^3=(a-3)(a^2+3a+9) ans.
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