Question

solve using identity(2p+q)²​

Answer 1

(2p+q)^2. _____ (a+b)^2__ a=2p,b=q

2p^2 + q^2 +2(2p)(q)

2p^2 +q^2 +4pq

Thanks

Answer 2

Answer:

$\Huge \boxed{4p^2+4pq+q^2}$

Step-by-step explanation:

To solve this problem, first you have to use the perfect square formula of $\displaystyle (c+d)^2=c^2+2cd+d^2$. You can also used distributive property of $\displaystyle a(b+c)=ab+ac$.

$\displaystyle C=2p\\\\\displaystyle D=q$

First, rewrite the problem down.

$\displaystyle (2p)^2+2*2pq+q^2$

Next, solve.

Multiply numbers from left to right.

$\displaystyle (2p)^2=2*2=4p^2$

$\displaystyle 2*2pq=4pq$

$\displaystyle \boxed{4p^2+4pq+q^2}$

$\bigstar\large\boxed{\textnormal{Finally, the final answer is \boxed{4p^2+4pq+q^2}}}}.\bigstar$